Vector Is Not A Template
Vector Is Not A Template - The code is parsed in the order it appears. The same result can however be achieved by simply including in the header file, this way you are not dependant on the order of inclusion. Since you're passing a pointer to a vector you need to dereference it. This however is rather unwielding. Vector in the function signature. If we start in node.h, early on, it includes edge.h. Therefore the compiler needs to know the declaration of std::vector at that point (amongst.</p> Vector is a template, not a type, you need the template argument list e.g. Building on what ganesh said, if you arrived here anytime after 2019, you need #include and the std::vector to use a vector. As some commenters have noted, you have circular references.
Vector is a template, not a type, you need the template argument list e.g. The code is parsed in the order it appears. Vector in the function signature. This however is rather unwielding. Therefore the compiler needs to know the declaration of std::vector at that point (amongst.</p> If we start in node.h, early on, it includes edge.h. As some commenters have noted, you have circular references. The same result can however be achieved by simply including in the header file, this way you are not dependant on the order of inclusion. Building on what ganesh said, if you arrived here anytime after 2019, you need #include and the std::vector to use a vector. Since you're passing a pointer to a vector you need to dereference it.
Vector is a template, not a type, you need the template argument list e.g. Therefore the compiler needs to know the declaration of std::vector at that point (amongst.</p> This however is rather unwielding. The same result can however be achieved by simply including in the header file, this way you are not dependant on the order of inclusion. Vector in the function signature. Building on what ganesh said, if you arrived here anytime after 2019, you need #include and the std::vector to use a vector. If we start in node.h, early on, it includes edge.h. As some commenters have noted, you have circular references. Since you're passing a pointer to a vector you need to dereference it. The code is parsed in the order it appears.
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The same result can however be achieved by simply including in the header file, this way you are not dependant on the order of inclusion. Therefore the compiler needs to know the declaration of std::vector at that point (amongst.</p> Vector is a template, not a type, you need the template argument list e.g. If we start in node.h, early on,.
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Vector in the function signature. The code is parsed in the order it appears. If we start in node.h, early on, it includes edge.h. As some commenters have noted, you have circular references. Building on what ganesh said, if you arrived here anytime after 2019, you need #include and the std::vector to use a vector.
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Since you're passing a pointer to a vector you need to dereference it. Building on what ganesh said, if you arrived here anytime after 2019, you need #include and the std::vector to use a vector. If we start in node.h, early on, it includes edge.h. The same result can however be achieved by simply including in the header file, this.
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As some commenters have noted, you have circular references. Building on what ganesh said, if you arrived here anytime after 2019, you need #include and the std::vector to use a vector. Vector in the function signature. The same result can however be achieved by simply including in the header file, this way you are not dependant on the order of.
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The code is parsed in the order it appears. As some commenters have noted, you have circular references. The same result can however be achieved by simply including in the header file, this way you are not dependant on the order of inclusion. Since you're passing a pointer to a vector you need to dereference it. Vector in the function.
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As some commenters have noted, you have circular references. Vector is a template, not a type, you need the template argument list e.g. If we start in node.h, early on, it includes edge.h. Since you're passing a pointer to a vector you need to dereference it. This however is rather unwielding.
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Since you're passing a pointer to a vector you need to dereference it. The code is parsed in the order it appears. Vector is a template, not a type, you need the template argument list e.g. If we start in node.h, early on, it includes edge.h. Therefore the compiler needs to know the declaration of std::vector at that point (amongst.</p>
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The code is parsed in the order it appears. As some commenters have noted, you have circular references. This however is rather unwielding. Since you're passing a pointer to a vector you need to dereference it. Building on what ganesh said, if you arrived here anytime after 2019, you need #include and the std::vector to use a vector.
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Vector is a template, not a type, you need the template argument list e.g. This however is rather unwielding. The code is parsed in the order it appears. Vector in the function signature. As some commenters have noted, you have circular references.
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The code is parsed in the order it appears. The same result can however be achieved by simply including in the header file, this way you are not dependant on the order of inclusion. Vector in the function signature. As some commenters have noted, you have circular references. Since you're passing a pointer to a vector you need to dereference.
Building On What Ganesh Said, If You Arrived Here Anytime After 2019, You Need #Include And The Std::vector To Use A Vector.
Since you're passing a pointer to a vector you need to dereference it. This however is rather unwielding. Therefore the compiler needs to know the declaration of std::vector at that point (amongst.</p> As some commenters have noted, you have circular references.
If We Start In Node.h, Early On, It Includes Edge.h.
Vector in the function signature. Vector is a template, not a type, you need the template argument list e.g. The same result can however be achieved by simply including in the header file, this way you are not dependant on the order of inclusion. The code is parsed in the order it appears.